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WATT Wt Batterymetal

19.0875
-0.3825 (-1.96%)
31 May 2024 - Closed
Delayed by 15 minutes
Name Symbol Market Type
Wt Batterymetal LSE:WATT London Exchange Traded Fund
  Price Change % Change Price Bid Price Offer Price High Price Low Price Open Price Traded Last Trade
  -0.3825 -1.96% 19.0875 18.84 19.335 - 3 16:35:25

Wt Batterymetal Discussion Threads

Showing 26 to 45 of 50 messages
Chat Pages: 2  1
DateSubjectAuthorDiscuss
27/3/2003
21:35
I=AYE or EYE
pizzaman
25/3/2003
12:52
maxk
1000 watts = 1kw so 32200 watts = 3.22kw
powered off the mains its still = 13amps * 240 volts = 3.12K

He needs a 3.3 kv to power the welder .
Thats a big generator to power his welder at max output.

portable generators usually come in around 2.2 kv .
Just enough to boil a kettle and no more.
Thats assuming its a 2kw kettle .
Trust Me .
LOL

gerry2
24/3/2003
21:45
Be carefull with your answers this could be an Iraqi trying to
obtain western secrets of arc welder.That chopper could be back
in the air tomorrow.

tapender
24/3/2003
21:18
LOL !

Dont forget its low voltage....32kw @ 240v = the national grid.

You wont weld it, you'll vaporise it.


ps, cant remember the conversion thingies....13 amp should be ok.

maxk
24/3/2003
21:13
gerry

bit late don't you think? wonging is in north midx nursing burns and shock

pizzaman
24/3/2003
19:39
wonging

Watts = V x I = 230 Volts * 140 amps = 32200 watts .

generator required 3.3 kva should be ample or ADVFN

LOL

Regards
Gerry

gerry2
17/3/2003
16:46
wonking

did your welder explode?

ARE YOU OK?!

pizzaman
17/3/2003
10:54
wonging - 17 Mar'03 - 10:16 - 5 of 17


pizzaman, ok thanks for the info, but this poses a question, i have used the generator via an extention lead with a max rating fully unwound of only 3000 watts, so are you saying i was pulling 6000 watts through this lead? what is I and R?

R= resistance and running the extention lead could be a problem.

6Kw will do you just fine IMO DYOR

PS i got one for sell in my garage and it's full of petrol LOL!

pizzaman
17/3/2003
10:49
If the welder runs off a 13A household supply the maximum power needed is
13A X 240 V = 3120 W (it is slightly more complex due to Power factor and other things but close enough)

The welder will not use all of this but you should be looking for a 3KW genny

gersman
17/3/2003
10:44
still needs a generator of around 6kw even if he is running only a 3Kw welder on it
pizzaman
17/3/2003
10:44
wooden5

AYE!

pizzaman
17/3/2003
10:43
in actual fact the name 1500 gives you a clue.i would say power consumption is 1500 watts
wooden5
17/3/2003
10:36
dell
correct there will be info on max amp draw on the machine x that by 240v will give you the size of the gen set needed.a welder transforms the 240v down to very low voltages high amps

wooden5
17/3/2003
10:32
dell

AYE!

pizzaman
17/3/2003
10:31
Power = VI

Assuming your welder runs on normal mains via a normal 13A plug, it can't be any more than 3KW or the fuse would blow instantly.

(240Vx13A=3120W absolute max)

DYOR.
(I would expect there to be a power consumption or input current printed on the welder somewhere)

dell314
17/3/2003
10:28
optimist, ok thanks for the info, its a conventional arc welder by the way
wonging
17/3/2003
10:25
I also= AYE+EYE
pizzaman
17/3/2003
10:20
If it will run on 230V then around 3000 VA should be enough but you will need more.

Arc welders put a highly inductive load on the supply which ups the current requirement and may not do your generator much good especially when you short circuit the welding tip.

Is yours a CO2 or conventional arc welder? If the latter I suggest that you look for a combined generator and welder. Also try to get something that will give you more than 140 amps.

optimist
17/3/2003
10:18
I=current
R=resistance

pizzaman
17/3/2003
10:16
pizzaman, ok thanks for the info, but this poses a question, i have used the generator via an extention lead with a max rating fully unwound of only 3000 watts, so are you saying i was pulling 6000 watts through this lead? what is I and R?
wonging
Chat Pages: 2  1